Solve for x:

Question

(2e^2x)-(7e^x)=15

Answer 1

let e^x = y
then you have
2y^2 - 7y - 15 = 0
(y - 5)(2y + 3) = 0
y = 5 or y = -3/2

e^x = 5
then x = ln5

or

e^x = -3/2
no solution, look at a graph of y = e^x, it is never negative

Answer 2

Thanks