AC^2 = AB^2 + BC^2
AC^2 = 3^2 +4^2
AC = 9 + 16
AC^2 = 25
AC = sq(25)
= 5
Solve for the length of the unknown side in the following right triangle. (Side AC is the hypotenuse.) Round your answer to two places, where applicable.
Side AB Side BC Side AC
3
4
?
2 answers
And since it is a Pythagorean Triple we know it is a 3,4, 5 triangle : )