Solve for s in the following equation: 11s+3+4=5.

Question

s=
wrong answer 2/11
Correct answers:
8

tell me why it's right in 2 sentyence

Answer 1

To solve for \( s \) in the equation \( 11s + 3 + 4 = 5 \), you first combine the constants on the left side: \( 11s + 7 = 5 \). Then, by isolating \( s \), you subtract 7 from both sides and divide by 11, leading to \( 11s = -2 \) and therefore \( s = -2/11 \), which contradicts the provided information that states \( s = 8 \) is correct. Thus, the correct answer must be verified from the initial equation to confirm tracing back to the given equation yields correct calculations.

Answer 2

Which correctly shows the area formula for a trapezoid, A=12h(b1+b2), rearranged for the quantity of interest h?
Responses

h=2Ab1+b2
h is equal to the fraction with numerator 2 cap A and denominator b sub 1 plus b sub 2 - not selected, this is the correct answer

b1=2Ah−b2
b sub 1 is equal to 2 cap A over h minus b sub 2 - incorrect

h=12A(b1+b2)
h is equal to 1 half cap A open paren b sub 1 plus b sub 2 close paren - no response given

h=b1+b22A

tell me why in 2 sentence

Answer 3

To rearrange the area formula for a trapezoid \( A = \frac{1}{2}h(b_1 + b_2) \) to solve for \( h \), you first multiply both sides by 2 to get \( 2A = h(b_1 + b_2) \), and then divide by \( (b_1 + b_2) \) to isolate \( h \), resulting in \( h = \frac{2A}{b_1 + b_2} \). The correct response accurately reflects this step by step rearrangement, confirming that \( h \) is equal to the fraction with a numerator of \( 2A \) and a denominator of \( b_1 + b_2 \).