Solve for d.

15<6d–3

11 answers

To solve the inequality \( 15 < 6d - 3 \), follow these steps:

  1. Add 3 to both sides: \[ 15 + 3 < 6d \] \[ 18 < 6d \]

  2. Divide by 6: \[ \frac{18}{6} < d \] \[ 3 < d \]

This can also be written as: \[ d > 3 \]

So, the solution is \( d > 3 \).

Solve for d.
3 - –1d≤1

To solve the inequality \( 3 - (-1d) \leq 1 \), we first rewrite it:

  1. Rewrite the negative sign: \[ 3 + d \leq 1 \]

  2. Subtract 3 from both sides: \[ d \leq 1 - 3 \] \[ d \leq -2 \]

So the solution is \( d \leq -2 \).

Solve for y.
1≥y/7–1

To solve the inequality \(1 \geq \frac{y}{7} - 1\), follow these steps:

  1. Add 1 to both sides: \[ 1 + 1 \geq \frac{y}{7} \] \[ 2 \geq \frac{y}{7} \]

  2. Multiply both sides by 7 (since 7 is positive, the direction of the inequality does not change): \[ 2 \cdot 7 \geq y \] \[ 14 \geq y \]

This can also be written as: \[ y \leq 14 \]

So, the solution is \(y \leq 14\).

Solve for p.
p/2–1<4

To solve the inequality \( \frac{p}{2} - 1 < 4 \), follow these steps:

  1. Add 1 to both sides: \[ \frac{p}{2} < 4 + 1 \] \[ \frac{p}{2} < 5 \]

  2. Multiply both sides by 2 (since 2 is positive, the direction of the inequality does not change): \[ p < 5 \cdot 2 \] \[ p < 10 \]

So, the solution is \( p < 10 \).

Solve for g.
4g+20>4

To solve the inequality \( 4g + 20 > 4 \), follow these steps:

  1. Subtract 20 from both sides: \[ 4g + 20 - 20 > 4 - 20 \] \[ 4g > -16 \]

  2. Divide both sides by 4: \[ g > \frac{-16}{4} \] \[ g > -4 \]

So, the solution is \( g > -4 \).

Solve for r.
2r+1≥9

To solve the inequality \( 2r + 1 \geq 9 \), follow these steps:

  1. Subtract 1 from both sides: \[ 2r + 1 - 1 \geq 9 - 1 \] \[ 2r \geq 8 \]

  2. Divide both sides by 2: \[ r \geq \frac{8}{2} \] \[ r \geq 4 \]

So, the solution is \( r \geq 4 \).

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