Asked by Jordaine
Solve each system of equations using substitution.
1.) x+3y=-4
y+x=0
2.) y=2x+3
5x-y=-3
3.) 2y=-4x
4x+2=-11
1.) x+3y=-4
y+x=0
2.) y=2x+3
5x-y=-3
3.) 2y=-4x
4x+2=-11
Answers
Answered by
Steve
Since these are all similar, I'll do one and you can come on back if you get stuck or just want confirmation of your answers.
#2:
y=2x+3
5x-y=-3
from the first equation,
y = 2x+3
Now substitute that into the second equation:
5x - (2x+3) = -3
3x - 3 = -3
3x = 0
x = 0
so, y = 3
#2:
y=2x+3
5x-y=-3
from the first equation,
y = 2x+3
Now substitute that into the second equation:
5x - (2x+3) = -3
3x - 3 = -3
3x = 0
x = 0
so, y = 3
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