Solve the system of equations. 7x+3y=−25 −7x+9y=−47(. What’s the answer

Answer 1

To solve this system of equations, we can use the method of elimination.

First, let's multiply the first equation by 7 and the second equation by -1 to make the x coefficients cancel each other out:

(7)(7x) + (7)(3y) = (7)(-25)
(-1)(-7x) + (-1)(9y) = (-1)(-47)

This simplifies to:

49x + 21y = -175
7x - 9y = 47

Now, add the two equations together to eliminate x:

49x + 21y + 7x - 9y = -175 + 47
56x + 12y = -128

Divide by 4 to simplify:

14x + 3y = -32

Now we have a new equation:

14x + 3y = -32
7x + 3y = -25

Subtracting the second equation from the first:

14x - 7x = -32 + 25
7x = -7
x = -1

Now substitute x back into one of the original equations to solve for y:

7(-1) + 3y = -25
-7 + 3y = -25
3y = -18
y = -6

Therefore, the solution to the system of equations is x = -1 and y = -6.

Answer 2

Solve the system of equations. –x+6y=13 4x–10y=–10. What’s the answer

Answer 3

To solve this system of equations, we can use the method of substitution or elimination.

From the first equation, we can isolate x:

-x + 6y = 13
-x = -6y + 13
x = 6y - 13

Now, we substitute this expression for x into the second equation:

4(6y - 13) - 10y = -10
24y - 52 - 10y = -10
14y - 52 = -10
14y = 42
y = 42/14
y = 3

Now that we have found the value of y, we can substitute it back into the expression we found for x:

x = 6(3) - 13
x = 18 - 13
x = 5

Therefore, the solution to the system of equations is x = 5 and y = 3.