Solve each of the following quadratic equations.
can some explain how to do these kinds of problems
4x^2=13x+12
i believe if i am understanding this i am supose to add to where i get =0
4x^2-13x+12=0
now what do i need to do
I am thinking factoring but I am not sure how to do this part
your equation should have been
4x^2 - 13x - 12 = 0
It does factor, I will give you a hint:
one of the factors is x-4
You must have been taught at least one general method to factor those quadratics that do factor.
It has been a while since i worked with any algebra
but i think i can remember some so this is what i got see if i am correct please
4x^2-13x-12=0
(4x+3)(x-4)=0
4x+3=0 0r x-4=0
4x=-3
4x/4=-3/4
x=-3/4
x-4=0
x=4
(-3/4,4)
did i do this right
yes, good for you.
it seems to be correct
1 answer