To solve this equation, we need to isolate the absolute value term |3p-1| and then consider its two possible cases:
1-|3p-1| = 0
or
-1+|3p-1| = 0
To isolate the absolute value term, we can rewrite the equation as:
|3p-1| = 1
Now we consider the two cases:
Case 1:
3p-1 = 1
or
3p-1 = -1
Solving for p in each case, we get:
p = 2/3
or
p = 0
Case 2:
-3p+1 = 1
or
-3p+1 = -1
Solving for p in each case, we get:
p = 0
or
p = 2/3
Therefore, the solution set for the equation 1-|3p-1| = 0 is {0, 2/3}.
To show the solution set on a number line, we can mark 0 and 2/3 on the line and shade the corresponding intervals:
<=======o-----------o=======>
-1 0 2/3 1
Solve each of the following equations. Show its solution set on a number line.
1-I3p+1I=0
Thank you!
1 answer