Question

Solve each equation by using square roots, show all work.
2x^2-5=27

Answer 1

hi again

so first, you need to add 5 to both sides of the equation, so it becomes

2x^2 = 32

next, you divide BOTh sides by 2 because you are going reverse order of operations. this gets rid of the 2 in front of the x^2. so the equation becomes

x^2 = 32/2 which is
x^2 = 16

next, you find the square root of both sides. i dont have a symbol on my keyboard for square root but lets pretend

ok so the square root of x^2 is x. then you must find the square root of 16 (the other side of the equation), but when you take square root, it become PLUS or MINUS . so it would be PLUS or MINUS the square root of 16.

the positive square root of 16 is 4,and the negative of the square root of 16 is -4.

your answers are x = 4 and x = -4 :D

message back on this post if u have more questions