(2y -x) dy = y dx
2 y dy - x dy = y dx
2 y dy = x dy + y dx
y^2 = x y + c
when x = 0
y^2 = c = 1
y^2 = x y + 1
Solve dy/dx = y/(2y-x) using rational substitution (using v=y/x) with the initial condition y(0)=1.
I solved this problem and found C (the constant) to be undefined. That is not the correct answer.
1 answer