next time, show your work, so we can find your error.
From equation 1, x = 2y-5
plug that into #2, and you have
x^2+y^2 = 25
(2y-5)^2 + y^2 = 25
5y^2 - 20y + 25 = 25
5y(y-4) = 0
y = 0 or 4
now you can find x values as needed, from either equation.
http://www.wolframalpha.com/input/?i=plot+2y+-+x+%3D+5,+x2+%2B+y2+-+25+%3D+0
Solve the system by the substitution method. Show your work.
2y - x = 5
x2 + y2 - 25 = 0
I solved the problem but I got it wrong for some reason..can you solve it step by step?
2 answers
That is exactly what I had for my answer but I was confused that I had an answer of 2 solutions.
4 answers