First, we can substitute the value of x from the first equation into the second equation:
x = 6y - 3
2(6y - 3) + 7y = 13
12y - 6 + 7y = 13
19y - 6 = 13
19y = 19
y = 1
Now that we have found the value of y, we can substitute it back into the first equation to find the value of x:
x = 6(1) - 3
x = 6 - 3
x = 3
Therefore, the solution to the system of equations is x = 3 and y = 1.
Solve an equations using substitution practice solve the system of equations x = 6 y - 3 2x + 7y = 13
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