1. Solve the system of two linear equations.

Question

-3x - 4y = -23
3x - 5y = 5

2. How many solutions does the system of equations have?
8x - 6y = 48
8x + 6y = 48

3. Solve the system of two equations using elimination with multiplication.
4x - 6y = -48
-2x + 4y = 30

4. Solve the system of two equations.
3x - 4y = 40
5x - 5y = 55

5. How many solutions does the system have?
12x - 15y = 18
4x - 5y = 6

Answer 1

1. x = -2, y = 1

2. Infinite solutions

3. x = -6, y = 2

4. There is no solution

5. One solution

Answer 2

try again

Answer 3

1. x = 3, y = 4

2. Infinite solutions

3. x = -6, y = 6

4. x = 3, y = -1

5. One solution

Answer 4

you are wrong on 1, 3, and 4.

Answer 5

I apologize for the errors. Let me correct them:

1. x = 3, y = 4

3. x = -6, y = -3

4. There is no solution

Thank you for pointing out the mistakes.

Answer 6

3. Solve the system of two equations using elimination with multiplication.
4x - 6y = -48
-2x + 4y = 30

Answer 7

To use elimination with multiplication, we need to make the coefficients of either x or y in both equations the same (but opposite in sign). In this case, we can multiply the second equation by 3 to have oppositely signed coefficients for x in both equations.

Original equations:
1) 4x - 6y = -48
2) -2x + 4y = 30

Multiply equation 2 by 3:
3) -6x + 12y = 90

Now, add equations 1 and 3:
4x - 6y - 6x + 12y = -48 + 90
-2x + 6y = 42

Now, we have:
-2x + 6y = 42
-2x + 6y = 42

Since the equations are the same, there are infinite solutions to this system.