6y^2 - 17y + 12 = 0
(3y-4)(2y-3) = 0
now finish it off
Solve 6y2=17y-12
2 answers
6y^2 - 17y + 12 = 0
(3y - 4)(2y - 3) = 0
y = 4/3 or y = 3/2
I assume you would know how to factor this trinomial
(3y - 4)(2y - 3) = 0
y = 4/3 or y = 3/2
I assume you would know how to factor this trinomial