solve.
3x/2 + 8-4x/7=3
3 answers
i got -70/13
how did you do that
3x/2 + 8-4x/7=3
The denominators are 2 and 7, and the LCM for them is their product: 2 x 7 = 14. So multiply through (multiply each term on both sides of the equation) by 14 to eliminate the fractions.
14(3x/2) + 14(8) + 14(-4x/7) = 14(3)
21x + 112 - 8x = 42
combine like terms
21x - 8x + 112 = 42
13x + 112 = 42
isolate x: start by subtraction 112 from both sides
13x = 42 - 112
combine like terms
13x = -70
divide both sides by 13 to get x by itself
x = -70/13
The denominators are 2 and 7, and the LCM for them is their product: 2 x 7 = 14. So multiply through (multiply each term on both sides of the equation) by 14 to eliminate the fractions.
14(3x/2) + 14(8) + 14(-4x/7) = 14(3)
21x + 112 - 8x = 42
combine like terms
21x - 8x + 112 = 42
13x + 112 = 42
isolate x: start by subtraction 112 from both sides
13x = 42 - 112
combine like terms
13x = -70
divide both sides by 13 to get x by itself
x = -70/13
8 answers