Solve 3x^1/2 + 5 - 2x^-1/2 = 0

Answer 1

3√x + 5 - 2/√x = 0
let y = √x

3y + 5 - 2/y = 0
multiply each term by y
3y^2 + 5y - 2 = 0
(3y - 1)(y + 2) = 0
y = 1/3 or y = -2

then √x = 1/3 , x = 1/9
or
√x = -2 , x is not a real number

x = 1/9 is the only real solution.

Answer 2

Slove the following equation 7(2x+1)-3-2x