solve 2cos^2x = square root of three cosx (couldnt find the sign on keyboard sorry) for principal values of x. express the solutions in degrees

Answer 1

2 cos^2 x = sqrt (3 cos x)
Note: cos x must be + to have a real square root, so only in quadrants 1 and 4)

4 cos^4 x = 3 cos x

cos^3 x = 3/4

cos x = .75^(1/3)

cos x = .90856

x = 25.1 deg or 360-25.1 deg

Answer 2

Thank you very much!