Solve 2cos^2(x) + 4sin(x)-3 = 0, giving all solutions in the interval 0 ≤ x ≤ 2π

3 answers

I already did this today
180-30
360 - 30

270 in degrees

multiply degrees by pi/180 to get radians if that is what you need
http://www.jiskha.com/display.cgi?id=1447870446
oh, you changed a number

2 (1 -sin^2) + 4 sin - 3 = 0

2 - 2 sin^2 + 4 sin - 3 = 0

-2 sin^2 + 4 sin - 1 = 0

2 sin^2 - 4 sin + 1 = 0

(2 sin -1)(2 sin-1) = 0
sin = 1/2
angle = 30 or 150 degrees