well, if cos^2(2x) = 1/2,
cos(2x) = ±1/√2, so
2x = π/4 or 3π/4 or 5π/4 or 7π/4
That means that x is π/8,3π/8,...
Solve 2cos^2(2x)=1
I divided both sides by 2 and got this
cos^2(2x)=1/2
But then I didn't know what to do after that... The part that has me stumped is that it's a cos^2(2x) not just a cos^2x. Any advice on what I should try next?
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