Solve 22 x 3 in expanded form. Fill in the blanks

Question

(20 + ?) x 3
(20 x ?) + (2 x 3)
? + 6 = 66

Answer 1

Let's solve the problem step by step in expanded form.

1. We start with \( 22 \times 3 \).
2. We rewrite 22 as \( 20 + 2 \).

So, we have: \[ (20 + 2) \times 3 \]

3. By using the distributive property, we can expand this: \[ (20 + 2) \times 3 = (20 \times 3) + (2 \times 3) \]

4. Now we calculate \( 20 \times 3 = 60 \) and \( 2 \times 3 = 6 \).

So, we can fill in: \[ (20 + 2) \times 3 = (20 \times 3) + (2 \times 3) = 60 + 6 \]

5. Finally, we have to fill in the equations based on the given statements:

• From \( (20 + ?) \times 3 \), we can see that \( ? \) is \( 2 \) since \( 20 + 2 = 22 \).
• The next part, \( (20 \times ?) + (2 \times 3) \) needs \( ? \) which is \( 3 \) since we get \( 20 \times 3 = 60 \).
• The last part \( ? + 6 = 66 \) gives us \( ? = 60 \).

So, filling in the blanks:

• \( (20 + 2) \times 3 \)
• \( (20 \times 3) + (2 \times 3) \)
• \( 60 + 6 = 66 \) (therefore the answer to the last blank is 60).

Thus, the completed equations are: \[ (20 + 2) \times 3 \] \[ (20 \times 3) + (2 \times 3) \] \[ 60 + 6 = 66 \]

Answer 2

Solve 14 x 3 in expanded form. Fill in the blanks
(10 + 4) x 3
(10 x ?) + (4 x 3)
30 + ? = 42

Answer 3

To solve \( 14 \times 3 \) in expanded form, we'll start from what you provided.

1. First, we rewrite \( 14 \) as \( 10 + 4 \): \[ (10 + 4) \times 3 \]

2. Now we can use the distributive property to expand this: \[ (10 + 4) \times 3 = (10 \times 3) + (4 \times 3) \]

3. Next, we calculate \( 10 \times 3 \) and \( 4 \times 3 \):

   • \( 10 \times 3 = 30 \)
   • \( 4 \times 3 = 12 \)

So, we can fill in the expressions: \[ (10 + 4) \times 3 = (10 \times 3) + (4 \times 3) = 30 + 12 \]

Now, to fill in the blanks:

• The expression \( (10 + 4) \times 3 \) shows \( ? = 4 \).
• The expression \( (10 \times ?) + (4 \times 3) \) requires \( ? = 3 \) for \( (10 \times 3) = 30 \).
• The last part \( 30 + ? = 42 \) shows that \( ? = 12 \) since \( 30 + 12 = 42 \).

So we have:

• \((10 + 4) \times 3\)
• \((10 \times 3) + (4 \times 3)\)
• \(30 + 12 = 42\)

Therefore, the completed solution is:

• \( ? = 4 \)
• \( ? = 3 \)
• \( ? = 12 \)