Let's break down the problem step by step.
First, we can expand 31 and 11:
- 31 can be expressed as \(30 + 1\).
- 11 can be expressed as \(10 + 1\).
Now we can write the multiplication as follows:
\[ 31 \times 11 = (30 + 1) \times (10 + 1) \]
Next, we apply the distributive property (often referred to as the FOIL method in this context):
\[ (30 + 1) \times (10 + 1) = 30 \times 10 + 30 \times 1 + 1 \times 10 + 1 \times 1 \]
Now we calculate each of these multiplications:
- \(30 \times 10 = 300\)
- \(30 \times 1 = 30\)
- \(1 \times 10 = 10\)
- \(1 \times 1 = 1\)
Now, we add all these results together:
\[ 300 + 30 + 10 + 1 = 341 \]
So, the final answer is:
31 x 11 = (30 + 1) x (10 + 1)
If we were to add all these up together, we would get the product of 341.