15t^2 + 7t -2 = 0
(5t-1)(3t+2) = 0
t = -2/3, 1/5
solve
15t^2+7t=2
2 answers
t =(-b�}�ã(b^2-4ac))/2a
t =(-7�}�ã(7^2-4(15)(-2)))/(2(15))
t=(-7�}�ã(49 +120))/30
t=(-7�}�ã169)/30
t=(-7�}13)/30
t=(-7+13)/30 = 6/30 = 1/5
t=(-7-13)/30 = -(20/30) = -(2/3)
Therefore, t = 1/5 & -(2/3)
t =(-7�}�ã(7^2-4(15)(-2)))/(2(15))
t=(-7�}�ã(49 +120))/30
t=(-7�}�ã169)/30
t=(-7�}13)/30
t=(-7+13)/30 = 6/30 = 1/5
t=(-7-13)/30 = -(20/30) = -(2/3)
Therefore, t = 1/5 & -(2/3)
1 answer