or
ln (2-x) = 14
e^{ln(2-x) = 2-x
so
2-x = e^14
x = 2 - e^14
x = - 1202602
Solve 14 - ln(2-x)=0. solve for x
-ln(2-x)=-14
ln 1/(2-x)=-14
1=-14(2-x)
1=-28+14x
29=14x
29/14=x
not sure where I'm going wrong
2 answers
You need to remove the natural log by writing both sides of the equation to base ''e''.
e^{ln(2-x)} = e^14
Applying the law of logarithms on the LHS:
2 - x = e^14
So:
x = 2 - e^14
e^{ln(2-x)} = e^14
Applying the law of logarithms on the LHS:
2 - x = e^14
So:
x = 2 - e^14