solve:

14. ln(1/x) = -2
16. lnx + ln(x+2) = ln(x+6)
22. ln(lnx) = 1

1 answer

I will do one
a) take the antilog of each side

1/x=e^-2
x= e^2

b) remember ln a + ln b= ln(a/b)
c) antilog ln x= e^x
ln e^0=1

I will be happy to critique your thinking.
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