Solutions of sodium carbonate and silver nitrate react to form solid silver carbonate and a solution of sodium nitrate. A solution containing 3.10 of sodium carbonate is mixed with one containing 4.43 of silver nitrate.

Question

How many grams of silver nitrate are present after the reaction is complete?

Answer 1

2AgNO3 + Na2CO3 ==> 2NaNO3 + Ag2CO3(s)
Before we can do anything you must identify 3.10 what and 4.43 what.
This is a limiting reagent problem (LR) and you know that because amounts are given for BOTH reactants. I work these the long way. I will assume those are grams.
mols AgNO3 = grams/molar mass = ?
mols Na2CO3 = grams/molar mass = ?

Using the coefficients in the balanced equation, convert mols AgNO3 to mols Ag2CO3.
Do the same and convert mols Na2CO3 to mols Ag2CO3.
It is likely that the two values will not agree which means one of them is not right; the correct value in LR problems is ALWAYS the smaller value and the reagent responsible for producing that number is the LR.

Now use the smaller number of mols Ag2cO3 and convert that to grams Ag2CO3.
g = mols x molar mass.