You're only choice is to work the problem and see. This is a limiting reagent (LR) problem and you know that because amounts are given for BOTH reactants. I work these the long way.
2Na(s) + Cl2(g) = 2NaCl(s)
mols Na = grams/molar mass
mols Cl2 = grams/molar mass
Using the coefficients in the balanced equation, convert mols Na to mols NaCl.
Do the same to convert mols Cl2 to mols NaCl.
It is likely that the two values will not be the same which means one of them is not right; the correct value in LR problems is ALWAYS the smaller value and the reagent responsible for that value is the LR.
Now use the smaller value and convert that to grams NaCl.
g NaCl = mols NaCl x molar mass NaCl.
Compare with the stuent's value.
sodium burns in chlorine to produce sodium chloride according to the reaction: 2Na(s) + Cl2(g) = 2NaCl(s). A student is asked to predict the mass of sodium chloride produced when 71 g of sodium is placed in a container of 200 g of chorine. The container is heated until the reaction occurs. The student gives the answer as 271 grams. Is this the correct answer? why or why not
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