Sodium azide (NaN3) yields N2 gas when heated to 300 degrees Celsius , a reaction used in automobile airbags. If 1.00 mol of N2 has a volume of 47.0 liters under the reaction conditions , how many liters of gas can be formed by heating 35g of NaN3?

Question

The reaction is 2Nan3------>3N2(g)+2Na

Answer 1

35g of NaN3*(1 mole/65.01g of NaN3)= moles of NaN3

moles of NaN3*(3 moles of N2/2 moles of NaN3)=moles of N2

moles of N2*(47 L/1 mole of N2)= volume in L.