parallel lines have the same slope
perpendicular lines have slopes which are negative reciprocals. That is, m1 * m2 = -1
The line x-y=0 has slope=1
so, the point-slope form of the line you want is
y+2 = 1(x-3)
to change that to slope-intercept form, you want y = mx+b, so it's just a matter of rearranging the data
y+2 = 1(x-3)
y = x-3 - 2
y = x-5
The perpendicular line has slope -1, so it is thus
y+2 = -1(x-3)
y = -x+3 - 2
y = -x+1
Do the other line the same way.
So I need help with 2 questions. This is what is being asked. Write the slope-intercept forms of the equations of the lines through the given point (a) parallel to the given line and (b) perpendicular to the given line.
1. (3, -2) x - y =0
2. (-4, 1) y + 2 = 0
Please Help and Thank You
2 answers
L00K 1T UP G1R|_ F431ND
2 answers