b.
Assuming a) is correct, then
1/2 m vf^2=mgh (ke at bottom=pe at top)
h=1/2 vf^2/g=about 10.3^2 /2*9.8=5.41
I am wondering about significant digits. Your speed after collision is two digits, yet you got correct the part a) with three digits...Then you put in two digits for a)...
Skier A of mass 71kg slides down a slope and makes a completely inelastic collision with Skier B, who is stationary, and has a mass of 55kg.Immediately after the collision both skiers have a speed of 5.8m/s.
a)Find the speed of skier A immediately before the collision. (I got this part, 10.3m/s)
b) If skier A slid down the hill with a starting velocity of 0m/s, what is the vertical height of the slope? (I don't get this one, I tried with y=v^2/2g and got 5.4 but its not the right answer)
2 answers
I'm guessing the answer sheet has some mistake? It says the height is 9.6m , which I can't seem to figure out how they got that number! :s