hyperbola
center at (-2,-4)
eccentricity = √2
asymptotes y+4 = ±(x+2)
vertices at x = ±2.5
foci at x = ±5√2
Sketch the graph: (x+2)^2/25-(y+4)^2/25=1
I don't understand this at all! When I tried graphing it I just had two lines going through the center, which is (-2,-4). But it should be a hyperbola, right? Could anyone help me?
3 answers
Oops
vertices at (-2±5,-4)
vertices at (-2±5,-4)
So do I draw lines through the vertices?