Sketch the graph of this quadratic function: f(x)= 3(x-2)^2 -10. Be sure to explain the steps you take.

**I don't need help with the graph part but I need to find the x and y intercepts, the equation of the axis of symmetry and the coordinates of the vertex from the function above. If someone could please provide help, that would be great. Thanks in advance.

1 answer

f(x) = 3x^2 - 12x + 2

the y-intercept is clearly at 2.

x-intercepts? where y=0. Use the quadratic formula to get

x = 2±√(10/3)