sinx+sinxcot^2x=cscx

prove each identity

2 answers

sinx + sinxcot^2x = sinx (1 + cot^2x)
= sinx*(sin^2+cos^2)/sin^2
= 1/sinx
= csc x
LS = sinx(1 + cot^2x)
= sinx(csc^2x)
= sinx(1/sin^2x)
= 1/sinx
= cscx
= RS
Similar Questions
  1. My previous question:Verify that (secx/sinx)*(cotx/cscx)=cscx is an identity. (secx/sinx)*(cotx/cscx) = (secx/cscx)(cotx/sinx) =
    1. answers icon 2 answers
  2. Prove the following:[1+sinx]/[1+cscx]=tanx/secx =[1+sinx]/[1+1/sinx] =[1+sinx]/[(sinx+1)/sinx] =[1+sinx]*[sinx/(sinx+1)]
    1. answers icon 3 answers
  3. Prove the following trig identity:1 + sinx = sinx(1+cscx)
    1. answers icon 1 answer
    1. answers icon 1 answer
more similar questions