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sinx+sinxcot^2x=cscx prove each identity

  1. sinx+sinxcot^2x=cscxprove each identity
    1. answers icon 2 answers
    2. tom asked by tom
    3. views icon 1,023 views
  2. My previous question:Verify that (secx/sinx)*(cotx/cscx)=cscx is an identity. (secx/sinx)*(cotx/cscx) = (secx/cscx)(cotx/sinx) =
    1. answers icon 2 answers
    2. Jon asked by Jon
    3. views icon 919 views
  3. Prove the following:[1+sinx]/[1+cscx]=tanx/secx =[1+sinx]/[1+1/sinx] =[1+sinx]/[(sinx+1)/sinx] =[1+sinx]*[sinx/(sinx+1)]
    1. answers icon 3 answers
    2. Anonymous asked by Anonymous
    3. views icon 938 views
  4. Prove the following trig identity:1 + sinx = sinx(1+cscx)
    1. answers icon 1 answer
    2. Anonymous asked by Anonymous
    3. views icon 456 views
  5. prove identity cscx-(cosx)(cotx)=sinx
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    2. logan asked by logan
    3. views icon 1,073 views
  6. Prove the identitycscx+cotx-1/cotx-cscx+1 = 1+cosx/sinx
    1. answers icon 3 answers
    2. Anonymous asked by Anonymous
    3. views icon 1,730 views
  7. Varify the identity cscx(cscx-sinx)+sinx-cosx/sinx + cot?
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    2. clarence asked by clarence
    3. views icon 466 views
  8. Verify that (secx/sinx)*(cotx/cscx)=cscx is an identity.(x=theta BTW)
    1. answers icon 1 answer
    2. Jon asked by Jon
    3. views icon 632 views
  9. Find a numerical value of one trigonometric function of x iftanx/cotx - secx/cosx = 2/cscx a) cscx=1 b) sinx=-1/2 c)cscx=-1
    1. answers icon 1 answer
    2. Lucy asked by Lucy
    3. views icon 957 views
  10. express in sinx1 1 ---------- + -------- cscx + cotx cscx - cotx and express in cosx 1 + cot x ------- - sin^2x cscx = 1/sinx so
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    2. linds asked by linds
    3. views icon 776 views