Sin5x cos2x + cos5x sin2x=

1 answer

It matches the pattern of
sin(A+B) = sinAcosB + cosAsinB

sin5x cos2x + cos5x sin2x
= sin(5x+2x)
= sin (7x)

Similar Questions

Simplify:(cosx + cos2x + cos3x + cos4x + cos5x + cos6x) / (sinx + sin2x + sin3x + sin4x + sin5x + sin6x) into a single Cotangent
1. 2 answers
Solve identity,(1-sin2x)/cos2x = cos2x/(1+sin2x) I tried starting from the right side, RS: =(cos²x-sin²x)/(1+2sinxcosx)
1. 3 answers
write sin4xcos2 as the sum or difference of two functions. answers: 1/2(cos6x+cos2x), 1/2(cos2x-cos6x), 1/2(sin6x+sin2x),
1. 0 answers
Verify the trigonometric identity:[(1–sin²x)/sin²x]–[(csc²x–1)/cos²x]= -tan²x I still can't figure this out.
1. 2 answers