Sin5x cos2x + cos5x sin2x=

Sin5x cos2x + cos5x sin2x=
1. 1 answer
2. asked by Becky
3. 2,245 views
Simplify:(cosx + cos2x + cos3x + cos4x + cos5x + cos6x) / (sinx + sin2x + sin3x + sin4x + sin5x + sin6x) into a single Cotangent
1. 2 answers
2. asked by Jeff
3. 1,690 views
Solve identity,(1-sin2x)/cos2x = cos2x/(1+sin2x) I tried starting from the right side, RS: =(cos²x-sin²x)/(1+2sinxcosx)
1. 3 answers
2. asked by sh
3. 736 views
Hi, I need help differentiating this equationy=(cos5x) (e^-5x ) This is what I tried to do.... -5 (sin5x) (e^-5x) + 5 (e^-5x)
1. 1 answer
2. asked by SC
3. 468 views
Solve the equation of the interval (0, 2pi)cosx=sinx I squared both sides to get :cos²x=sin²x Then using tri indentites I came
1. 4 answers
2. asked by Brian
3. 782 views
solve for (<_ = less than or equal to / pie = pie sign / -pie = negative pie)3 sin²x = cos²x ; 0 <_ x < 2pie cos²x - sin²x =
1. 3 answers
2. asked by Julie
3. 1,050 views
sinx = 4/5 and x terminates in Quadrant IIFind sin2x and cos2x How to get the answers, which are sin2x = -24/25, cos2x = -7/25?
1. 1 answer
2. asked by Amandeep
3. 1,740 views
Been trying this forever so it says: Simplify 1+sin2x+cos2x/1+sin2x-cos2xive tried this problem so many times I need help with
1. 1 answer
2. asked by Maria
3. 1,510 views
prove sin2x+cos2x+1 tan(pi/4+x)______________ = __________ sin2x+cos2x-1 tanx so what I did tan(x)
1. 2 answers
2. asked by Lana
3. 734 views
value of expression (cos5x + cos3x)/ (sin5x - sin3x) where x = (3.14/8)
1. 1 answer
2. asked by jignesh
3. 707 views