sin^4cos^2x=(1/16)(1-cos 2x)(1-cos4x)

work one 1 side only!

1 answer

pick x=50ยบ
LS = .202..
RS = .379..

Your equation is NOT an identity

I assumed your LS = sin^x4cos^2x
you had sin^2[cos^2x], but I doubt that is what you meant.
(that would be even worse)
Similar Questions
  1. sin^4 x = (3-4cos 2x + cos4x)/8prove on one side please!
    1. answers icon 4 answers
  2. Prove:cos4x = 8cos^4x - 8cos^2x + 1 My Attempt: RS: = 4cos^2x (2cos^2x - 1) + 1 = 4 cos^2x (cos2x) + 1 LS: = cos2(2x) =
    1. answers icon 38 answers
    1. answers icon 0 answers
  3. Prove thatcos4x=8cos^4x-8cos^2x+1 so I'm guessing you begin with the left side cos4x=cos2(2x) then im kinda lost
    1. answers icon 2 answers
more similar questions