sin^4cos^2x=(1/16)(1-cos 2x)(1-cos4x) work one 1

  1. sin^4cos^2x=(1/16)(1-cos 2x)(1-cos4x)work one 1 side only!
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    2. hayden asked by hayden
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  2. Prove:cos4x = 8cos^4x - 8cos^2x + 1 My Attempt: RS: = 4cos^2x (2cos^2x - 1) + 1 = 4 cos^2x (cos2x) + 1 LS: = cos2(2x) =
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    2. Anonymous asked by Anonymous
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  3. sin^4 x = (3-4cos 2x + cos4x)/8prove on one side please!
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    2. Rachel asked by Rachel
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  4. What am I doing wrong?Equation: sin2x = 2cos2x Answers: 90 and 270 .... My Work: 2sin(x)cos(x) = 2cos(2x) sin(x) cos(x) =
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    2. Anonymous asked by Anonymous
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  5. Prove thatcos4x=8cos^4x-8cos^2x+1 so I'm guessing you begin with the left side cos4x=cos2(2x) then im kinda lost
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    2. Natash asked by Natash
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  6. sin^4 x (cos^2 x)=(1/16)(1-cos 2x)(1-cos4x)work one 1 side only!
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    2. Hayden asked by Hayden
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  7. Several questions from my homework, any are appreciated. Thanks!Solve: 1) sinx-tanx=0 2) 3csc^2x=4 Find all solutions within
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    2. Michael asked by Michael
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  8. Find all solutions to the equation in the interval [0, 2pi)cos4x-cos2x=0 So,this is what i've done so far: cos4x-cos2x=0
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    2. Maria asked by Maria
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  9. Write an equation for simple harmonic motion, given that the amplitude equals 4 inches and the period equals 2 seconds and the
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    2. Kayla asked by Kayla
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  10. How can I find the exact value of 4cos(7ð/4)-2sin(ð/3) without using a calculator (show work)?
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    2. Anonymous asked by Anonymous
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