x^2+6x+8 = (x+2)(x+4)
x^2-2x-8 = (x+2)(x-4)
The other one is
(x-6)(x+6) * x^2(x+4)
--------------------------------
x(x+6) * (x-6)(x+2)
Now you should be able to cancel factors and figure any excluded values (where the denominator is zero)
- Simplify: x^2+6x+8/x^2-2x-8 . Identify any excluded values
- Simplify :
x^2-36/x^2+6x * x^3+4x^2/x^2-4x-12
1 answer