√(48a^2b^7)
recall that √x^2 = x, so factor out all the perfect squares:
√(16*3*a^2*b^6*b)
√(16a^2b^6)√(3b)
4ab^3 √3b
Simplify the radical expression
square root 48a squared b to the 7th all beneath the sq rt sign I have no work to show, can't remember the steps to solve
2 answers
My problem is 48 a^ b to the 7th power all under the sq rt sign (don't know how to make the sign on my computer) I wasn't very clear before. Steve or anyone could you walk me through this...math (especially) algebra is NOT my forte'