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Simplify the polynomial expression (xy−2)(x2+1) .(2 points) x3y+ x2+ xy+Asked by Hana blanie
Simplify the polynomial expression (xy−2)(x2+1)
.(2 points)
x3y+
x2+
xy+
.(2 points)
x3y+
x2+
xy+
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Answered by
GPT-4o mini
To simplify the polynomial expression \((xy - 2)(x^2 + 1)\), we can use the distributive property (also known as the FOIL method for binomials).
Let's distribute each term in the first polynomial by each term in the second polynomial:
\[
(xy - 2)(x^2 + 1) = xy \cdot x^2 + xy \cdot 1 - 2 \cdot x^2 - 2 \cdot 1
\]
Now, we can simplify each term:
1. \(xy \cdot x^2 = x^3y\)
2. \(xy \cdot 1 = xy\)
3. \(-2 \cdot x^2 = -2x^2\)
4. \(-2 \cdot 1 = -2\)
Putting it all together, we get:
\[
x^3y + xy - 2x^2 - 2
\]
So the simplified expression is:
\[
x^3y - 2x^2 + xy - 2
\]
Thus, the simplified polynomial expression is:
\[
x^3y + xy - 2x^2 - 2
\]
Let's distribute each term in the first polynomial by each term in the second polynomial:
\[
(xy - 2)(x^2 + 1) = xy \cdot x^2 + xy \cdot 1 - 2 \cdot x^2 - 2 \cdot 1
\]
Now, we can simplify each term:
1. \(xy \cdot x^2 = x^3y\)
2. \(xy \cdot 1 = xy\)
3. \(-2 \cdot x^2 = -2x^2\)
4. \(-2 \cdot 1 = -2\)
Putting it all together, we get:
\[
x^3y + xy - 2x^2 - 2
\]
So the simplified expression is:
\[
x^3y - 2x^2 + xy - 2
\]
Thus, the simplified polynomial expression is:
\[
x^3y + xy - 2x^2 - 2
\]
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