Asked by Dawn
write a polynomial that expresses the area of a rectangle whose length is 3 feet more than twice the width
Answers
Answered by
dongo
Let x denote the width of the rectangle, measured in ft..
The height h is by virtue of the assignment defined as h(x)= 2*x+3. Again, the measurement's unit is ft..
The area of a rectangle is calculated by:
Area(h, x) = h*x
Substituting h=h(x)=2*x+3, we obtain the final result:
Area(h, x) = (2*x+3)*x = 2*x²+3x. This is measured in square-ft.
The height h is by virtue of the assignment defined as h(x)= 2*x+3. Again, the measurement's unit is ft..
The area of a rectangle is calculated by:
Area(h, x) = h*x
Substituting h=h(x)=2*x+3, we obtain the final result:
Area(h, x) = (2*x+3)*x = 2*x²+3x. This is measured in square-ft.
Answered by
Dawn
THANKS DONGO!!
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