sin(360-x) = -sin(x)
tan(-x) = -tan(x)
cos(180-x) = -cos(x)
so, you have
sin(x)tan(x)/cos(x) = sin^2(x)/cos^2(x) = tan^2(x)
Not sure where the A comes from, but you get the idea. Just reduce everything to simple trig functions and then combine them. If you need further help, please fix all the typos and get back to us.
Simplify the following expression to a single trigonometric term sin(360-x)*tan(-x)/cos(180 x)*(sin^2A cos^2A) answer= -sinx*-tanx/cosx*(1) after that how do i continue?
1 answer