i-5/2i
what i see nah
Simplify the expression
-5+i/2i
-5+i over 2i
4 answers
(-5+i)/2i = -5/(2i) + 1/2
Now, 1/i = -i, since i^2 = -1
Thus we end up with
1/2 + 5/2 i
or (1+5i)/2
Now, 1/i = -i, since i^2 = -1
Thus we end up with
1/2 + 5/2 i
or (1+5i)/2
just learn something god bless u sir
It all comes with experience. You might just note that the powers of i cycle in periods of 4:
i^-4 = 1
i^-3 = 1/i^3 = 1/-i = i
i^-2 = 1/i^2 = -1
i^-1 = 1/i = -i
i^0 = 1
i^1 = i
i^1 = -1
i^3 = -i
i^4 = 1
...
i^-4 = 1
i^-3 = 1/i^3 = 1/-i = i
i^-2 = 1/i^2 = -1
i^-1 = 1/i = -i
i^0 = 1
i^1 = i
i^1 = -1
i^3 = -i
i^4 = 1
...