How did you get that minus ?
I had (6x - 14 + 2x^3)/x^4
Simplify the complex fraction
((3x-7)/x^2)/(x^2/2)+(2/x)
Is this answer right?
(6x-14-2x^3)/(x^4)
4 answers
You make little mistake.
[ ( 3 x - 7 ) / x² ] / ( x² / 2 ) + 2 / x =
2 • ( 3 x - 7 ) / ( x² • x² ) + 2 / x=
( 6 x - 14 ) / x⁴ + 2 / x =
( 6 x - 14 ) / x⁴ + 2 • x³ / x⁴=
( 2 x³ + 6 x - 14 ) / x⁴ =
2 ( x³ + 3 x - 7 ) / x⁴
[ ( 3 x - 7 ) / x² ] / ( x² / 2 ) + 2 / x =
2 • ( 3 x - 7 ) / ( x² • x² ) + 2 / x=
( 6 x - 14 ) / x⁴ + 2 / x =
( 6 x - 14 ) / x⁴ + 2 • x³ / x⁴=
( 2 x³ + 6 x - 14 ) / x⁴ =
2 ( x³ + 3 x - 7 ) / x⁴
"I'm confused" you make mistake, not mathhelper.
Bosnian is correct, he simply factored out the 2 for a better answer
3 answers