Simplify \(-\frac{3}{4}r\ +\ 3\ -\ \frac{5}{6}r\ -\ 6\). (1 point)

1 answer

To simplify the expression \(-\frac{3}{4}r + 3 - \frac{5}{6}r - 6\), we will first combine like terms.

  1. Combine the constant terms: \(3 - 6\). \[ 3 - 6 = -3 \]

  2. Combine the \(r\) terms: \(-\frac{3}{4}r - \frac{5}{6}r\).

    To combine the \(r\) terms, we need a common denominator. The least common multiple of \(4\) and \(6\) is \(12\).

    • Convert \(-\frac{3}{4}r\) to have a denominator of \(12\): \[ -\frac{3}{4}r = -\frac{3 \times 3}{4 \times 3}r = -\frac{9}{12}r \]
    • Convert \(-\frac{5}{6}r\) to have a denominator of \(12\): \[ -\frac{5}{6}r = -\frac{5 \times 2}{6 \times 2}r = -\frac{10}{12}r \]
  3. Now, combine these two converted terms: \[ -\frac{9}{12}r - \frac{10}{12}r = -\frac{9 + 10}{12}r = -\frac{19}{12}r \]

  4. Putting it all together, the simplified expression is: \[ -\frac{19}{12}r - 3 \]

Thus, the simplified expression is \(\boxed{-\frac{19}{12}r - 3}\).

Similar Questions
    1. answers icon 1 answer
    1. answers icon 1 answer
    1. answers icon 1 answer
  1. Let $a,$ $b,$ $c$ be complex numbers such that\begin{align*} \frac{a}{b + c} + \frac{b}{c + a} + \frac{c}{a + b} &= 0, \\
    1. answers icon 1 answer
more similar questions