Write the ratios for sin~A and cos~A The triangle is not drawn to scale.

Question

A

50

14

B

48

(1 point)

sin~A=\frac{14}{50} cos~A=\frac{48}{50}

sin~A=\frac{48}{50}, cos~A=\frac{14}{50}

sin~A=\frac{48}{14} cos~A=\frac{14}{50}

sin~A=\frac{48}{50}, cos~A=\frac{14}{48}

Answer 1

The correct answer is:

sin~A = 14/50, cos~A = 48/50