Simplify:

Question

3xy + 6x^2 4xy - 2y^2
___________ ____________
* then
2y 9x^2 y^2


/ (divide by) 4x^2 - y^2

Thank you so much!! :)))

Answer 1

let me rewrite it again

3xy + 6x^2 4xy - 2y^2
___________ ___________
*
2y 9x^2 y^2

then
divide it by (4x^2 - y^2)

Answer 2

the first fraction
3xy + 6x^2
___________

2y

then multiply to other fraction
4xy - 2y^2
___________

9x^2 y^2

divide by (4x^2 - y^2)

sorry for the errors and please answer me.

Answer 3

write it like this:

(3xy + 6x^2)/(2y) * (4xy - 2y^2)/(9x^2 y^2) * 1/((4x^2 - y^2)
factor it ...
= 3x(y + 2x)/(2y) * 2y(2x - y)/(3xy)^2 * 1/((2x-y)(2x+y))
= 1/(3x y^2)