simplify 10P4
210
360
5,040
151,200
I think 360
22 answers
That's incorrect. Give it another try.
10! /(10-4)! = 10!/6! = 10*9*8*7 = 5040
Damon is correct.
just gonna mention, tho, that normally you shouldn't give them the direct answer
thx Damon!
Emma -- please do not criticize unless you have all of the facts. Damon is a long time official tutor here and a retired university professor. He knows what he is doing.
I don't mean to be rude Ms. Sue BUT HOW ARE WE SUPPOSED TO KNOW THAT PLZ EXPLAIN!!!!!!!
YOU ACT LIKE WE ARE SUPPOSED TO KNOW THAT!!!!
I'm sorry Ms. Sue, but I didn't know that and was simply saying what I thought were the rules (and what another tutor told me).
A reasonable person keeps his mouth shut unless he knows the situation. Grow up!
Speaking of people keeping their mouths shut until they know the situation... there's no reason for you to tell me to grow up. I was just trying to inform Damon of what I thought had been told were the rules. I apologized and admitted I was wrong, all while being polite. You didn't need to be rude. I normally avoid losing my temper, but just because you're a tutor doesn't mean that you can go around making unkind assumptions about people. For your information, most people would consider me very mature. Also, I'm sure you'll delete this comment because you don't want to be embarrassed, but I'm still saying this because someone has to.
So you deleted the other person's comment but not mine? That hardly seems fair...
THAT'S SO TRUE. (I just was spectating)
bruh Ms. Sue had no right to be so rude
15. Simplify 10P4. (1 point)
O210
O 360
O 5,040
O 151,200
O210
O 360
O 5,040
O 151,200
The answer is 5,040.
Simplify 15C3. (1 point)
O 182
O 455
O2,730
0910
O 182
O 455
O2,730
0910
The answer is 455.
You and 5 friends go to a concert. In how many different ways can you
sit in the assigned seats?
(1 point)
O 720
O 120
O 30
O 15
sit in the assigned seats?
(1 point)
O 720
O 120
O 30
O 15
We can use the formula of permutation. The number of arrangements of n distinct objects taken r at a time is given by the formula:
nPr = n! / (n-r)!
Here, n=6 (you and 5 friends) and r=6 (number of seats).
So, the number of ways you can sit in the assigned seats is:
6P6 = 6! / (6-6)! = 6! / 0! = 6 x 5 x 4 x 3 x 2 x 1 = 720
Therefore, the answer is 720.
nPr = n! / (n-r)!
Here, n=6 (you and 5 friends) and r=6 (number of seats).
So, the number of ways you can sit in the assigned seats is:
6P6 = 6! / (6-6)! = 6! / 0! = 6 x 5 x 4 x 3 x 2 x 1 = 720
Therefore, the answer is 720.
You own 5 pairs of jeans and want to take 2 of them with you on vacation. In how many ways can you choose 2 pairs of jeans?
(1 point)
10 ways
O 15 ways
O 4 ways
O 20 ways
(1 point)
10 ways
O 15 ways
O 4 ways
O 20 ways
We can use the combination formula. The number of combinations of n distinct objects taken r at a time is given by the formula:
nCr = n! / r!(n-r)!
Here, n=5 (number of pairs of jeans) and r=2 (number of pairs to be chosen).
So, the number of ways you can choose 2 pairs of jeans is:
5C2 = 5! / (2!3!) = 10
Therefore, the answer is 10 ways.
nCr = n! / r!(n-r)!
Here, n=5 (number of pairs of jeans) and r=2 (number of pairs to be chosen).
So, the number of ways you can choose 2 pairs of jeans is:
5C2 = 5! / (2!3!) = 10
Therefore, the answer is 10 ways.