Simplify #1:

Question

cscx(sin^2x+cos^2xtanx)/sinx+cosx
= cscx((1)tanx)/sinx+cosx
= cscxtanx/sinx+cosx

Is the correct answer cscxtanx/sinx+cosx?

Simplify #2:
sin2x/1+cos2X
= ???

I'm stuck on this one. I don't know what I should do.

Simplify #3:
cosx-sin(90-x)sinx/cosx-cos(180-x)tanx
= cosx-(sin90cosx-cos90sinx)sinx/cosx-(cos180cosx+sinx180sinx)tanx
= cosx-sin90cosx+cos90sinxsinx/cosx-cos180cosx-sinx180sinxtanx
= cosx-sin90cosx+cos90sin^2x/cosx-cos180cosx-sinx180sinxtanx
= ???

What do I do next?

Please help and Thank you

Answer 1

#1
(1/sinx)(sin^2x + cos^2x(sinx/cosx) )/(sinx + cosx)
= (sinx + cosx)/(sinx+cosx)
= 1

#2
sin 2x/(1+ cos 2x)
= 2sinxcosx/(1 + 2sin^2x - 1)
= 2sinxcosx/2cos^2x
=sinx/cosx
= tan x

#3 new approach
remember that sin(90-x) = cosx
and cos(180-x) = -cosx , you are attempting to "prove" these in your solution

cosx-sin(90-x)sinx/cosx-cos(180-x)tanx
= cosx - cosx(tanx) - (-cosx)(tanx)
= cosx

Answer 2

I'm still confuse in #3

Answer 3

ok, let's go to your solution ....
from
cosx-(sin90cosx-cos90sinx)sinx/cosx-(cos180cosx+sinx180sinx)tanx
= cosx-((1)cosx-(0)sinx)(tanx) - ((-1)cosx+(0)sinx)tanx
= cosx - cosxtanx + cosxtanx
= cosx

Answer 4

I know where you're getting at but it's cosx-(sin90cosx-cos90sinx)sinx all over cosx-(cos180cosx+sin180sinx)tanx
sorry I should've put brackets to separate them.
[cosx-(sin90cosx-cos90sinx)sinx]/[cosx-(cos180cosx+sin180sinx)tanx]