Silver bromide, AgBr, decomposes into silver (Ag) solid and bromine, (Br 2

) liquid at room temperature. Which ratio of silver to bromine is in the products of the reaction?(1 point)
Responses

2:1
2:1

2:3
2:3

4:3
4:3

1:3

1 answer

The decomposition reaction of silver bromide (AgBr) can be represented as:

\[ 2 , \text{AgBr} \rightarrow 2 , \text{Ag} + \text{Br}_2 \]

From the balanced equation, we can see that for every 2 moles of silver bromide decomposing, 2 moles of silver (Ag) and 1 mole of bromine (Br₂) are produced.

To find the ratio of silver (Ag) to bromine (Br₂) in the products:

  • For every 2 moles of silver, there is 1 mole of bromine.

Thus, the ratio of silver to bromine is:

\[ \text{Ag:Br}_2 = 2:1 \]

Therefore, the correct answer is 2:1.