The decomposition reaction of silver bromide (AgBr) can be represented as:
\[ 2 , \text{AgBr} \rightarrow 2 , \text{Ag} + \text{Br}_2 \]
From the balanced equation, we can see that for every 2 moles of silver bromide decomposing, 2 moles of silver (Ag) and 1 mole of bromine (Br₂) are produced.
To find the ratio of silver (Ag) to bromine (Br₂) in the products:
- For every 2 moles of silver, there is 1 mole of bromine.
Thus, the ratio of silver to bromine is:
\[ \text{Ag:Br}_2 = 2:1 \]
Therefore, the correct answer is 2:1.